Perfect number
C++ Loops
sum of divisors
Flowchart (ISO 5807)
Source code
void perfect(int n) {
int sum = 0;
for (int i = 1; i < n; i++) {
if (n % i == 0) {
sum += i;
}
}
if (sum == n) {
cout << "Досконале";
} else {
cout << "Ні";
}
}